Mehdi Baghalagdam

most citedOn the Diophantine equation

\sum_{i = 1}^{n} a_{i} x_{i}^{4} = \sum_{j = 1}^{n} a_{j} y_{j}^{4}

2 citations · 4 across the 4 of their papers we have counts for

collaborators

4 papers

math.NT2017★ 2 cited

Is the quartic Diophantine equation $A^{4} + h B^{4} = C^{4} + h D^{4}$ solvable for any integer $h$ ?

Farzali Izadi, Mehdi Baghalagdam

The Diophantine equation $A^{4} + h B^{4} = C^{4} + h D^{4}$ , where $h$ is a fixed arbitrary positive integer, has been investigated by some authors. Currently, by computer search, the integer sol…

math.NT2017

On the sums of many biquadrates in two different ways

Farzali Izadi, Mehdi Baghalagdam

The beautiful quartic Diophantine equation $A^{4} + h B^{4} = C^{4} + h D^{4}$ , where $h$ is a fixed arbitrary positive integer, has been studied by some mathematicians for many years. Although Ch…

math.NT2017★ 2 cited

On the Diophantine equation $\sum_{i = 1}^{n} a_{i} x_{i}^{4} = \sum_{j = 1}^{n} a_{j} y_{j}^{4}$

Farzali Izadi, Mehdi Baghalagdam

In this paper, by using the elliptic curves theory, we study the fourth power Diophantine equation $\sum_{i = 1}^{n} a_{i} x_{i}^{4} = \sum_{j = 1}^{n} a_{j} y_{j}^{4}$ , where $a_{i}$ and $n \geq 3$ …

math.NT2017

On the Diophantine equations $\sum_{i = 1}^{n} a_{i} x_{i}^{6} + \sum_{i = 1}^{m} b_{i} y_{i}^{3} = \sum_{i = 1}^{n} a_{i} X_{i}^{6} \pm \sum_{i = 1}^{m} b_{i} Y_{i}^{3}$

Farzali Izadi, Mehdi Baghalagdam

In this paper, the elliptic curves theory is used for solving the Diophantine equations $\sum_{i=1}^n a_ix_{i} ^6+\sum_{i=1}^m b_iy_{i} ^3= \sum_{i=1}^na_iX_{i}^6\pm\sum_{i=1}^m b_…

Is the quartic Diophantine equation A4+hB4=C4+hD4 solvable for any integer h?

On the sums of many biquadrates in two different ways

On the Diophantine equation ∑i=1n​ai​xi4​=∑j=1n​aj​yj4​

On the Diophantine equations ∑i=1n​ai​xi6​+∑i=1m​bi​yi3​=∑i=1n​ai​Xi6​±∑i=1m​bi​Yi3​

Is the quartic Diophantine equation $A^{4} + h B^{4} = C^{4} + h D^{4}$ solvable for any integer $h$ ?

On the Diophantine equation $\sum_{i = 1}^{n} a_{i} x_{i}^{4} = \sum_{j = 1}^{n} a_{j} y_{j}^{4}$

On the Diophantine equations $\sum_{i = 1}^{n} a_{i} x_{i}^{6} + \sum_{i = 1}^{m} b_{i} y_{i}^{3} = \sum_{i = 1}^{n} a_{i} X_{i}^{6} \pm \sum_{i = 1}^{m} b_{i} Y_{i}^{3}$