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Zhi-Wei Sun
Let m be a positive integer, and define $$ζ_m(s)=\sum_{n=1}^\infty\frac{(-e^{2πi/m})^{ω(n)}}{n^s}\ \ \ \ \text{and} \ \ \ \ ζ^*_m(s)=\sum_{n=1}^\infty\frac{(-e^{2πi/m})^{Ω(n)}}{n…