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Ankit Mishra

5 papers hereh-index 14 citations5 works total

Matching runs newest-first, so older work may not be attached to this profile yet.

author position
  • first author5

Across the 5 of 5 papers where every author was matched, so the position is known.

fields
  • math.AC5
same name
  • Ankit Mishra — 4 papers, h 11
  • Ankit Mishra — 3 papers, h 3
  • Ankit Mishra — 1 paper, h 5
  • Ankit Mishra — 1 paper, h 2
  • Ankit Mishra — 1 paper, h 3

Either other researchers who publish under this name, or the same person where the external sources have not merged their records.

identity via Semantic Scholar / OpenAlex

activity
20202023
collaborators

5 papers

math.AC2023

A sub-functor for Ext and Cohen-Macaulay associated graded modules with bounded multiplicity-II

Ankit Mishra, Tony J. Puthenpurakal

Let (A,m) be a \CM\ local ring, then notion of T-split sequence was introduced in part-1 of this paper for m-adic filtration with the help of numerical…

math.AC2023

On associated graded modules of maximal Cohen-Macaulay modules over hypersurface rings-II

Ankit Mishra, Tony J. Puthenpurakal

If (A,m) is a hypersurface ring of dimension d with e(A)=3. Let M be an MCM A-module with μ(M)=4 then we prove that $\depth{G(M)}\geq d-3$.

math.AC2022

On associated graded modules of maximal Cohen-Macaulay modules over hypersurface rings

Ankit Mishra, Tony J. Puthenpurakal

Let A=Q/(f) where (Q,n) be a complete regular local ring of dimension d+1, f∈ni∖ni+1 for some i≥2 and M an MCM A−m…

math.AC2021

On associated graded modules of maximal Cohen-Macaulay modules over hypersurface rings

Ankit Mishra, Tony J. Puthenpurakal

Let (A,m) be a hypersurface ring with dimension d, and M a MCM A−module with red(M)≤2 and μ(M)=2 or 3 then we have proved that depth $G(M)\geq d-μ(M)+1…

math.AC2020

Cohen-Macaulay local rings with e2​=e1​−e+1

Ankit Mishra, Tony J. Puthenpurakal

In this paper we study Cohen-Macaulay local rings of dimension d, multiplicity e and second Hilbert coefficient e2​ in the case e2​=e1​−e+1. Let $h = μ(\mathfrak{m})…

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