Solving the Puzzle of $\frac{M_{D^{\ast }}-M_D}{M_{D_s^{\ast }}-M_{D_s}}$ $\simeq$ $\frac{M_{B^{\ast }}-M_B}{M_{B_s^{\ast }}-M_{B_s}}$ $\simeq$ $1$

Dae Sung Hwang, Gwang-Hee Kim

The commonly used Hamiltonian of the chromomagnetic hyperfine splitting is inversely proportional to the product of the masses of two constituent quarks composing the meson. So it…