paper

Discrete excursions

arXiv:math/0701171

Abstract

It is well-known that the length generating function E(t) of Dyck paths (excursions with steps +1 and -1) satisfies 1-E+t^2E^2=0. The generating function E^(k)(t) of Dyck paths of height at most k is E^(k)=F_k/F_{k+1}, where the F_k are polynomials in t given by F_0=F_1=1 and F_{k+1}= F_k-t^2F_{k-1}. This means that the generating function of these polynomials is \sum_{k\ge 0} F_k z^k= 1/(1-z+t^2z^2). We note that the denominator of this fraction is the minimal polynomial of the algebraic series E(t). This pattern persists for walks with more general steps. For any finite set of steps S, the generating function E^(k)(t) of excursions (generalized Dyck paths) taking their steps in S and of height at most k is the ratio F_k/F_{k+1} of two polynomials. These polynomials satisfy a linear recurrence relation with coefficients in Q[t]. Their (rational) generating function can be written \sum_{k\ge 0} F_k z^k= N(t,z)/D(t,z). The excursion generating function E(t) is algebraic and satisfies D(t,E(t))=0 (while N(t,E(t))\not = 0). If max S=a and min S=b, the polynomials D(t,z) and N(t,z) can be taken to be respectively of degree d_{a,b}=binomial(a+b,a) and d_{a,b}-a-b in z. These degrees are in general optimal: for instance, when S={a,-b} with a and b coprime, D(t,z) is irreducible, and is thus the minimal polynomial of the excursion generating function E(t). The proofs of these results involve a slightly unusual mixture of combinatorial and algebraic tools, among which the kernel method (which solves certain functional equations), symmetric functions, and a pinch of Galois theory.

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