Residual detuning in the laboratory-frame anti-Jaynes--Cummings model with a squeezed vacuum

Abstract

The laboratory-frame anti-Jaynes--Cummings (AJC) interaction retains a residual detuning $2f\lambda$ that is absent from the rotating-frame model. We map two proposed remedies---a Kerr shift $\chi ({\hat{a}}^{†}\hat{a}{)}^2$ and collective Dicke coupling of $N$ two-level emitters---for a squeezed vacuum on that ladder ($r=1$, $⟨n⟩={\sinh }^{2}r\simeq 1.38$). All quoted contrasts are the amplitude of the first turning point of the atomic ground-state population, which coincides with the two-level formula $\mathcal{C}=1/[1+(2f+\chi {)}^2]$ at $r=0$ to $10^{-9}$. Three results follow. (i)~A single Kerr strength never restores unit contrast at $r=1$; the $r=0$ $n$-dependent shift $\chi (2n+1)$ cannot cancel $2f\lambda$ on every occupied Fock component. (ii)~The exact $r=1$ contrast at $\chi =0$ is not reproduced by an incoherent sum ${\sum }_n{P}_n(r){\mathcal{C}}_n$ built from the $r=0$ two-level formula; pointwise deviations are several tenths. (iii)~Collective coupling raises the contrast systematically. At $f=5$ one finds $\mathcal{C}=0.140$ ($N=1$) and $\mathcal{C}=0.575$ ($N=8$), above the unsqueezed value $8/[8+(2f{)}^2]=0.074$. The $N=16$ point at this $f$ remains truncation-limited and is not quoted to three digits. The same $N\sim (2f{)}^2$ estimate for $\mathcal{C}=1/2$ places trapped-ion values $f\sim 10^2$--$10^3$ outside the present construction. The relevant platform is ultrastrong circuit QED with $f\sim 1$--$10$. The calculation is a numerical control landscape, not a new solvable limit.

15 pages, 7 figures. Submitted to Quantum Inf. Process