paper

Almost every Latin square has a decomposition into transversals

arXiv:2501.05438

Abstract

In 1782, Euler conjectured that no Latin square of order has a decomposition into transversals. While confirmed for by Tarry in 1900, Bose, Parker, and Shrikhande constructed counterexamples in 1960 for each with . We show that, in fact, counterexamples are extremely common, by showing that if a Latin square of order is chosen uniformly at random then with high probability it has a decomposition into transversals.

93 pages, 9 figures

Almost every Latin square has a decomposition into transversals · wovepaper