Taut visibility domains are not necessarily Kobayashi complete

Abstract

We answer a question asked recently by Banik in the negative by showing that for each $n\ge 2$, there exists a taut visibility domain in ${\mathbb{C}}^n$ that is not Kobayashi complete. The domains that we produce are bounded and have boundaries that are very regular away from a single point.

arXiv comment4 pages; added a reference and updated existing references. To appear in Proc. Amer. Math. Soc. Comments welcome!