Subdividing triangles with $\pi$-commensurable angles

Abstract

A point in the interior of a planar triangle determines a subdivision into six subtriangles. A triangle with angles commensurable with $\pi$ is called $\pi$-commensurable. For such a triangle a subdivision where each of the subtriangles are $\pi$-commensurable too is called $\pi$-commensurable. We prove that there are infinitely many $\pi$-commensurable triangles that do not admit any $\pi$-commensurable subdivision except the one given by angle bisectors. We count the number of $\pi$-commensurable subdivisions of triangles. We perform a similar count for Z-degree sub-divisions of Z-degree triangles too. Finally we show that subdivision by angle bisectors is essential in recursive subdivisions in the sense that recursive $\pi$-commensurable subdivisions of any $\pi$-commensurable triangle ultimately involve a subdivision by angle bisectors.

arXiv comment7 pages, 1 figure