paperAn identity for (−q5;q10)∞arXiv:2111.11857AbstractWe prove that n=0∏∞(1+q10n+5)=4∑n≥0(−q)2n(n+1)sin{10(2n+1)3π}∑n≥0(−q)2n(n+1)sin{10(2n+1)π}∑n=−∞∞qn2∑n=−∞∞(−1)n(−q)n(3n−1)/2∣q∣<1 using identities due to Ramanujan.3 pages