The Lawson number of a semitopological semilattice
arXiv:1910.00436 · doi:10.1007/s00233-021-10184-z
Abstract
For a Hausdorff topologized semilattice its is the smallest cardinal such that for any distinct points there exists a family of closed neighborhoods of in such that and is a subsemilattice of that does not contain . It follows that , where is the smallest cardinal such that for any point there exists a family of closed neighborhoods of in such that and . We prove that a compact Hausdorff semitopological semilattice is Lawson (i.e., has a base of the topology consisting of subsemilattices) if and only if . Each Hausdorff topological semilattice has Lawson number . On the other hand, for any infinite cardinal we construct a Hausdorff zero-dimensional semitopological semilattice such that and . A topologized semilattice is called (i) - if ; (ii) if each non-empty chain has and . We prove that for any complete subsemilattice of an -Lawson semitopological semilattice , the partial order of is closed in and hence is closed in . This implies that for any continuous homomorphism from a compete topologized semilattice to an -Lawson semitopological semilattice the image is closed in .
10 pages. arXiv admin note: text overlap with arXiv:1806.02868