Inequalities for the Schmidt Number of Bipartite States
arXiv:1902.11069 · doi:10.1007/s11005-019-01244-1
Abstract
In this short note we show two completely opposite methods of constructing entangled states. Given a bipartite state , define , , where is the flip operator. In the first method, entanglement is a consequence of the inequality . In the second method, there is no correlation between and . These two methods show how diverse is quantum entanglement. We prove that any bipartite state satisfies where stands for the Schmidt number of and are the marginal states of . We also present a family of PPT states in , whose members have Schmidt number equal to , for any given . This is a new contribution to the open problem of finding the best possible Schmidt number for PPT states.
arXiv commentIn this new version, our main inequality has been improved and the construction of a PPT state in with Schmidt number has been simplified
References in corpus (7)
- Separability Criterion for Density Matrices
- Separability of Mixed States: Necessary and Sufficient Conditions
- Entanglement detection
- A Schmidt number for density matrices
- Schmidt number witnesses and bound entanglement
- High-Dimensional Entanglement in States with Positive Partial Transposition
- A gap for PPT entanglement