Orlicz-Besov extension and Ahlfors -regular domains
arXiv:1901.06186
Abstract
Let and $ϕ: [0,\fz) \to [0,\infty)$ be a Young's function satisfying We show that Ahlfors -regular domains are Besov-Orlicz extension domains, which is necessary to guarantee the nontrivially of . On the other hand, assume that grows sub-exponentially at $\fz$ additionally. If is a Besov-Orlicz extension domain, then it must be Ahlfors -regular.