'Twisted duality' for Clifford Algebras

Abstract

Viewing the complex Clifford algebra $C(V)$ of a real inner product space $V$ as a superalgebra, we offer several proofs of the fact that if $W$ is a subspace of the complexification of $V$ then the supercommutant of the Clifford algebra $C(W)$ is precisely the Clifford algebra $C(W^{\perp })$.

8 pages

Cited by in corpus (2)

• 'Twisted duality' in the ${\mathrm{C}}^{\ast }$ Clifford algebra
• The Clifford algebra and its antidual