paper

Fibers of algebra

arXiv:1006.5900

Abstract

It is shown that Gelfand transforms of elements $f\in\lmu$ are constant at almost every fiber of the spectrum of $\lmu$ in the following sense: for each $f\in\lmu$ there is an open dense subset of this spectrum having full measure and such that the Gelfand transform of is constant on the intersection .

4 pages

Fibers of $L^{\infty}$ algebra · wovepaper