On the Davenport constant and group algebras
arXiv:0907.4913 · doi:10.4064/cm121-2-2
Abstract
For a finite abelian group and a splitting field of , let denote the largest integer for which there is a sequence over such that for all . If denotes the Davenport constant of , then there is the straightforward inequality . Equality holds for a variety of groups, and a standing conjecture of W. Gao et.al. states that equality holds for all groups. We offer further groups for which equality holds, but we also give the first examples of groups for which holds. Thus we disprove the conjecture.
12 pages; fixed typos and clearer proof of Lemma 3.9